Understanding Polynomials Before We Factor
Before we factor, we need to understand what a polynomial is.
A polynomial is an expression made up of terms added
or subtracted together. Each term has a coefficient (number) and
variables with exponents .
Example: 3x2 + 7x - 5
First term: 3x2 (coefficient is 3)
Second term: 7x (coefficient is 7)
Third term: -5 (this is a constant)
When we factor, we're finding what we can pull out of all terms.
Think of it like finding common ingredients in a recipe.
Method 1: Greatest Common Factor (GCF)
What is GCF?
The Greatest Common Factor is the largest number or variable
that divides evenly into all terms. It's like finding the
biggest piece that all terms share.
Understanding GCF
Look at 12x2 + 8x
What divides into 12? 1, 2, 3, 4, 6, 12
What divides into 8? 1, 2, 4, 8
What divides into both? 1, 2, 4 → Greatest is 4
Both terms also have at least one x , so our GCF is 4x.
Steps for GCF Factoring
Find the GCF of all coefficients
Find the lowest power of each variable that appears in every term
Factor out the GCF
Write what's left in parentheses
Detailed Example
Factor 6x3 + 9x2 - 12x
Step 1: GCF of numbers (6, 9, 12)
6 = 2 × 3
9 = 3 × 3
12 = 2 × 2 × 3
Common factor: 3
Step 2: Each term has at least one x → x1
Step 3: GCF = 3x
Step 4: 6x3 + 9x2 - 12x = 3x(2x2 + 3x - 4)
Practice Problem
Factor each polynomial using GCF:
5a + 10b
4x2 + 8x
15m3 + 10m2 - 5m
Method 2: Difference of Two Squares (DOTS)
What is DOTS?
DOTS stands for Difference Of Two Squares . This is when you have two perfect squares being
subtracted.
The pattern: a2 - b2 = (a + b)(a - b)
Recognizing Perfect Squares
A perfect square is a number or expression that can be written as something times itself.
Perfect Square Recognition
x2 = x × x → perfect square
4 = 2 × 2 = 22 → perfect square
9x2 = 3x × 3x = (3x)2 → perfect square
x = x1 → NOT a perfect square
3x2 → NOT a perfect square (3 isn't a perfect square)
How to Factor Using DOTS
Confirm both terms are perfect squares
Confirm there's a minus sign between them
Take the square root of each term
Write as (square root 1 + square root 2)(square root 1 - square root 2)
Detailed Example
Factor x2 - 25
Step 1: Is x2 a perfect square? Yes, square root is x
Step 2: Is 25 a perfect square? Yes, square root is 5
Step 3: Do we have a minus sign? Yes ✓
Step 4: x2 - 25 = (x + 5)(x - 5)
More Complex Example
Factor 9a4 - 16b2
Step 1: Square root of 9a4 = 3a2
Step 2: Square root of 16b2 = 4b
Step 3: Both are perfect squares with minus sign ✓
Step 4: 9a4 - 16b2 = (3a2 + 4b)(3a2 - 4b)
Practice Problem
Factor each polynomial using DOTS:
x2 - 16
4a2 - 9
m2 - 100n2
Method 3: Sum and Difference of Cubes (SDOTC)
What is SDOTC?
SDOTC handles Sum and Difference of cubes. These are similar to DOTS but
with cubes instead of squares.
Sum of Cubes: a3 + b3 = (a + b)(a2 - ab +
b2 )
Difference of Cubes: a3 - b3 = (a - b)(a2 + ab +
b2 )
Recognizing Perfect Cubes
A perfect cube is something multiplied by itself three times.
Perfect Cube Recognition
x3 = x × x × x → perfect cube
8 = 2 × 2 × 2 = 23 → perfect cube
27a3 = 3a × 3a × 3a = (3a)3 → perfect cube
64b6 = 4b2 × 4b2 × 4b2 = (4b2 )3 →
perfect cube
How to Factor Using Sum of Cubes
For a3 + b3 :
Find the cube roots: find a and b
Write the first binomial: (a + b)
For the trinomial: (a2 - ab + b2 )
Answer: (a + b)(a2 - ab + b2 )
Sum of Cubes Example
Factor x3 + 8
Step 1: Cube root of x3 = x and cube root of 8 = 2
Step 2: First binomial: (x + 2)
Step 3: Trinomial: (x2 - 2x + 4)
a2 = x2
ab = x × 2 = 2x (we put minus here)
b2 = 22 = 4
Step 4: x3 + 8 = (x + 2)(x2 - 2x + 4)
How to Factor Using Difference of Cubes
For a3 - b3 :
Find the cube roots: find a and b
Write the first binomial: (a - b)
For the trinomial: (a2 + ab + b2 ) ← Note: plus signs here
Answer: (a - b)(a2 + ab + b2 )
Difference of Cubes Example
Factor 27m3 - 64
Step 1: Cube root of 27m3 = 3m and cube root of 64 = 4
Step 2: First binomial: (3m - 4)
Step 3: Trinomial: (9m2 + 12m + 16)
a2 = (3m)2 = 9m2
ab = 3m × 4 = 12m (plus here!)
b2 = 42 = 16
Step 4: 27m3 - 64 = (3m - 4)(9m2 + 12m + 16)
Practice Problem
Factor each polynomial using SDOTC:
a3 + 27
b3 - 125
8x3 + 1
Method 4: Perfect Square Trinomials (PST)
What is a Perfect Square Trinomial?
A perfect square trinomial is when a binomial is squared. It follows a pattern:
(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 - 2ab + b2
When factoring, we reverse this process to find the original binomial.
Recognizing PST
Look for:
First term is a perfect square
Last term is a perfect square
Middle term equals 2 × square root of first × square root of last
Recognizing PST
Is x2 + 6x + 9 a perfect square trinomial?
First term: x2 → square root is x ✓
Last term: 9 → square root is 3 ✓
Middle check: 2 × x × 3 = 6x → matches! ✓
This IS a perfect square trinomial!
How to Factor PST
Take the square root of the first term
Take the square root of the last term
Determine the sign from the middle term
Write as (a ± b)2
PST Factoring Examples
Example 1: x2 + 8x + 16
Square root of x2 = x
Square root of 16 = 4
Middle term is positive: +8x
Answer: (x + 4)2
Example 2: 4a2 - 12a + 9
Square root of 4a2 = 2a
Square root of 9 = 3
Middle term is negative: -12a
Check: 2 × 2a × 3 = 12a ✓
Answer: (2a - 3)2
Practice Problem
Factor each polynomial if it's a perfect square trinomial:
m2 + 10m + 25
4b2 - 4b + 1
x2 + 5x + 4 (Is this PST?)
Method 5: Quadratic Trinomials (QT)
What are Quadratic Trinomials?
A quadratic trinomial is a polynomial with three terms in the form
ax2 + bx + c where a, b, and c are numbers.
When we can't use the other methods, we use the quadratic trinomial method.
The AC Method (Most Reliable)
Step 1: Multiply a × c
Step 2: Find two numbers that multiply to give ac and add to give b
Step 3: Rewrite the middle term using these two numbers
Step 4: Factor by grouping
AC Method - Simple Example
Factor x2 + 5x + 6
Step 1: a = 1, c = 6 → a × c = 6
Step 2: We need two numbers that:
Multiply to give 6: (1,6), (2,3)
Add to give 5 (the b value): 2 + 3 = 5 ✓
Step 3: Rewrite: x2 + 2x + 3x + 6
Step 4: Factor by grouping:
Group 1: x2 + 2x = x(x + 2)
Group 2: 3x + 6 = 3(x + 2)
Combined: (x + 2)(x + 3)
AC Method - More Complex
Factor 2x2 + 7x + 3
Step 1: a = 2, c = 3 → a × c = 6
Step 2: Two numbers that multiply to 6 and add to 7:
Pairs: (1,6), (2,3)
1 + 6 = 7 ✓
Step 3: Rewrite: 2x2 + 1x + 6x + 3
Step 4: Factor by grouping:
Group 1: 2x2 + 1x = x(2x + 1)
Group 2: 6x + 3 = 3(2x + 1)
Combined: (2x + 1)(x + 3)
Check: (2x + 1)(x + 3) = 2x2 + 6x + x + 3 = 2x2 + 7x + 3 ✓
When the Leading Coefficient is 1
When a = 1 (so we have x2 + bx + c), we can use a simpler method:
Find two numbers that multiply to c and add to b.
Simple Trinomial Factoring
Factor x2 - 7x + 10
We need two numbers that:
Multiply to 10: (1,10), (2,5)
Add to -7: -2 + (-5) = -7 ✓
Answer: (x - 2)(x - 5)
Practice Problem
Factor each quadratic trinomial:
x2 + 7x + 12
2x2 + 11x + 5
x2 - 6x + 8
Putting It All Together: Factoring Strategy
When you see a polynomial to factor, follow these steps:
Always check for GCF first! If there's a common factor, pull it out.
Count the terms:
2 terms? Check for DOTS or SDOTC
3 terms? Check for PST or use QT method
4+ terms? Try factoring by grouping
After factoring, check if you can factor again. Sometimes a factor can be factored
further!
Complete Factoring Example
Factor completely: 2x3 - 50x
Step 1: GCF → 2x(x2 - 25)
Step 2: We have (x2 - 25) with 2 terms. Is this DOTS?
x2 is a perfect square ✓
25 is a perfect square ✓
Minus sign ✓
Step 3: Factor DOTS: (x - 5)(x + 5)
Final Answer: 2x(x - 5)(x + 5)
Practice Problem
Factor each polynomial completely:
3a2 - 27
x3 + 6x2 + 9x
4b4 - 16b2
Lesson References & Sources:
Topics: Factoring Polynomials • Rational Algebraic Expressions (RAE) • Systems of Linear Equations
Oracion, V. C., III, & Oracion, C. C. (2004).
Elementary Algebra (5th ed.).
Quezon City, Philippines: Art Angel Printshop.
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