A rational algebraic expression is a fraction where the numerator and/or denominator contain variables. Think of it like a regular fraction, but with algebra instead of just numbers.
We can NEVER divide by zero. This means we must identify what values make the denominator equal to zero—these are not allowed.
For 5/(x - 2):
The denominator is zero when x - 2 = 0, so x = 2.
Domain restriction: x ≠ 2
For (x + 1)/((x - 3)(x + 5)):
The denominator is zero when x = 3 or x = -5.
Domain restrictions: x ≠ 3 and x ≠ -5
Before we do any operations, we should simplify rational expressions by canceling common factors.
Simplify (x2 - 1)/(x + 1)
Step 1: Factor the numerator: x2 - 1 = (x + 1)(x - 1)
Step 2: Denominator is already factored: (x + 1)
Step 3: Cancel the common factor (x + 1):
((x + 1)(x - 1))/(x + 1) = x - 1
Step 4: Simplified expression: x - 1 (where x ≠ -1)
Note: We still need to remember x ≠ -1 even though it cancels!
Simplify (6x2 + 12x)/(2x)
Step 1: Factor numerator: 6x2 + 12x = 6x(x + 2)
Step 2: Factor denominator: 2x = 2x
Step 3: Cancel common factors:
(6x(x + 2))/(2x) = (3(x + 2))/1 = 3(x + 2) = 3x + 6
Step 4: Simplified: 3x + 6 (where x ≠ 0)
Simplify each rational expression. State domain restrictions.
Multiplying rational expressions works just like multiplying fractions: multiply numerators together and denominators together.
Formula: A/B × C/D = (A × C)/(B × D) (where B ≠ 0 and D ≠ 0)
Multiply 3/x × x2/6
Step 1: Already factored
Step 2: (3 × x2)/(x × 6) = (3x2)/(6x)
Step 3: Cancel common factors (3 and x):
(3x2)/(6x) = x/2
Step 4: Answer: x/2 (where x ≠ 0)
Multiply ((x + 2)/(x - 3)) × ((x2 - 9)/(x2 - 4))
Step 1: Factor everything:
Step 2: Write as one fraction:
((x + 2)(x - 3)(x + 3))/((x - 3)(x - 2)(x + 2))
Step 3: Cancel (x + 2) and (x - 3):
(x + 3)/(x - 2)
Step 4: Answer: (x + 3)/(x - 2) (where x ≠ 2, -2, 3)
Multiply each pair of rational expressions. Simplify completely.
Dividing rational expressions uses a special trick: flip the second fraction and multiply instead.
Formula: A/B ÷ C/D = A/B × D/C (where B ≠ 0, C ≠ 0, D ≠ 0)
Divide 4/x ÷ 2/x3
Step 1-2: Keep first, flip second:
4/x × x3/2
Step 3: Combine:
(4 × x3)/(x × 2) = (4x3)/(2x)
Step 4: Simplify (cancel 2 and x):
2x2 (where x ≠ 0)
Divide ((x2 - 1)/(x + 2)) ÷ ((x - 1)/(3x + 6))
Step 1-2: Flip and change to multiply:
((x2 - 1)/(x + 2)) × ((3x + 6)/(x - 1))
Step 3: Factor everything:
((x - 1)(x + 1))/(x + 2) × (3(x + 2))/(x - 1)
Step 4: Cancel (x - 1) and (x + 2):
3(x + 1) = 3x + 3 (where x ≠ -2, 1)
Divide each pair of rational expressions. Simplify completely.
Adding fractions with variables works the same as adding numeric fractions. We need a common denominator.
When denominators are identical, just add the numerators.
Formula: A/C + B/C = (A + B)/C
Add x/(x + 1) + 3/(x + 1)
Since both have denominator (x + 1):
(x + 3)/(x + 1) (where x ≠ -1)
When denominators are different, find the least common denominator (LCD).
Steps:
Add 1/(2x) + 3/(4x)
Step 1-2: Factor denominators and find LCD:
Step 3: Rewrite with LCD:
Step 4: Add:
2/(4x) + 3/(4x) = 5/(4x) (where x ≠ 0)
Add 2/(x - 1) + 3/(x + 2)
Step 1: Denominators already factored
Step 2: LCD = (x - 1)(x + 2)
Step 3: Rewrite each fraction:
Step 4: Add numerators:
((2x + 4) + (3x - 3))/((x - 1)(x + 2)) = (5x + 1)/((x - 1)(x + 2))
Step 5: Cannot simplify further
Answer: (5x + 1)/((x - 1)(x + 2)) (where x ≠ 1, -2)
Add each pair of rational expressions. Simplify completely.
Subtracting rational expressions works the same as adding, except we subtract the numerators instead.
When subtracting, be careful to distribute the negative sign to all terms in the second numerator.
Formula: A/C - B/C = (A - B)/C
Subtract ((x + 2))/x - 3/x
((x + 2) - 3)/x = (x - 1)/x (where x ≠ 0)
Subtract x/(x + 1) - 2/(x + 2)
Step 1-2: LCD = (x + 1)(x + 2)
Step 3: Rewrite:
Step 4: Subtract (distribute the negative!):
((x2 + 2x) - (2x + 2))/((x + 1)(x + 2)) = (x2 - 2)/((x + 1)(x + 2))
Answer: (x2 - 2)/((x + 1)(x + 2)) (where x ≠ -1, -2)
Subtract each pair of rational expressions. Simplify completely.
When working with rational expressions:
Simplify (((x2 - 1))/(x + 2)) × ((x + 2)/(x - 1)) + 1/(x + 1)
Step 1: Do multiplication first (order of operations):
Factor: ((x - 1)(x + 1))/(x + 2) × (x + 2)/(x - 1)
Cancel (x - 1) and (x + 2): (x + 1)
Step 2: Now add: (x + 1) + 1/(x + 1)
Rewrite x + 1 = ((x + 1)2)/(x + 1)
(((x + 1)2 + 1))/(x + 1) = (x2 + 2x + 2)/(x + 1)
Answer: (x2 + 2x + 2)/(x + 1) (where x ≠ -1, -2)
Directions: Simplify each expression. State domain restrictions and show all work.